-16t^2+1000t=0

Solution for -16t^2+1000t=0 equation:

-16t^2+1000t=0

a = -16; b = 1000; c = 0;
Δ = b2-4ac
Δ = 10002-4·(-16)·0
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1000000}=1000$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-1000}{2*-16}=\frac{-2000}{-32}
=62+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+1000}{2*-16}=\frac{0}{-32}
=0
$